(2x^2-8x-24)/(2x-6)

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Solution for (2x^2-8x-24)/(2x-6) equation:


D( x )

2*x-6 = 0

2*x-6 = 0

2*x-6 = 0

2*x-6 = 0 // + 6

2*x = 6 // : 2

x = 6/2

x = 3

x in (-oo:3) U (3:+oo)

(2*x^2-(8*x)-24)/(2*x-6) = 0

(2*x^2-8*x-24)/(2*x-6) = 0

2*x^2-8*x-24 = 0

2*(x^2-4*x-12) = 0

x^2-4*x-12 = 0

DELTA = (-4)^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+4)/(1*2) or x = (4-64^(1/2))/(1*2)

x = 6 or x = -2

2*(x+2)*(x-6) = 0

(2*(x+2)*(x-6))/(2*x-6) = 0

( 2 )

2 = 0

x belongs to the empty set

( x+2 )

x+2 = 0 // - 2

x = -2

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -2, 6 }

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